You can put this solution on YOUR website! How many litres of a 30% acid solution should be added to 20 litres of 60% acid solution in order to obtain a 50% acid solution?
:
Let x = amt of 30% solution required
:
Write a decimal equiv, mixture equation
.30x + .60(20) = .50(x+20)
.30x + 12 = .5x + 10
12 - 10 = .5x - .3x
2 = .2x
x =
x = 10 liters of 30% stuff required