SOLUTION: can someone help me please? im really stuck simplify each complex fraction. 12x^2y^3/6z^5 over 3z^7/2xy

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Question 472189: can someone help me please? im really stuck
simplify each complex fraction.
12x^2y^3/6z^5 over 3z^7/2xy

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
your equation looks like this:
%28%2812x%5E2y%5E3%29%2F%286z%5E5%29%29+%2F+%28%283z%5E7%29%2F%282xy%29%29
since (a/b) / (c/d) is equivalent to (a/b) * (d/c), your equation is equivalent to:
%28%2812x%5E2y%5E3%29%2F%286z%5E5%29%29+%2A+%28%282xy%29%2F%283z%5E7%29%29
since (a/b) * (d/c) is equivalent to (a*d) / (b*c), then your equation is equivalent to:
%28%2812x%5E2y%5E3%29+%2A+%282xy%29%29+%2F%28%286z%5E5%29+%2A+%283z%5E7%29%29
By the laws of commutation, you can reorder the terms in a multiplication.
this means that a*d*g*b is equivalent to a*b*d*g.
your equation is therefore, equivalent to:
%2812%2A2%2Ax%5E2%2Ax%2Ay%5E3%2Ay%29+%2F%286z%5E5+%2A+3z%5E7%29
since a^b * a^c = a^(b+c), then your equation is equivalent to:
%2824%2Ax%5E3%2Ay%5E4%29+%2F%2818z%5E12%29
you can further simplify this to:
%284%2Ax%5E3%2Ay%5E4%29+%2F%283z%5E12%29
to confirm your answer is correct, simply replace x, y, and z with numbers and see if the original equation and the final equation give you the same answer.
i did that by making x = 2, y = 3, z = 4 and i was able to confirm that both the original equation and the final equation gave me the same answer.