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3x³–x²–3x+1
Factor x² out of the first two terms:
x²(3x-1)-3x+1
Factor -1 out of the last two terms:
x²(3x-1)-1(3x-1)
Factor out (3x-1)
(3x-1)(x²-1)
Factor the second parenthesis as the difference of two squares:
(3x-1)(x-1)(x+1)
Set each factor = 0
3x-1=0 x-1=0 x+1=0
3x=1 x=1 x=-1
x=
The zeros are
, 1, and -1
Edwin