SOLUTION: solve cosx(sinx-1/2)=0 [0-2/pi]

Algebra ->  Trigonometry-basics -> SOLUTION: solve cosx(sinx-1/2)=0 [0-2/pi]      Log On


   

Question 471776: solve cosx(sinx-1/2)=0 [0-2/pi]
Found 2 solutions by Tatiana_Stebko, oadeshina:
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
Answer by oadeshina(1) About Me  (Show Source):
You can put this solution on YOUR website!
cosx*(sinx-1\2)=0
either cosx=0 or sinx-1\2=0
if sinx-1\2=0, then sinx=1\2,sinx=0.5, x=sin^1*0.5
then x=30. thanks