SOLUTION: Part 1. The Burger Bin restaurant sells a mean of 24 burgers an hour and its burger sales are normally distributed. If hourly sales fall between 24 and 42 burgers 49.85% of the tim

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Question 471495: Part 1. The Burger Bin restaurant sells a mean of 24 burgers an hour and its burger sales are normally distributed. If hourly sales fall between 24 and 42 burgers 49.85% of the time, the standard deviation is _____ burgers. A. 3 B. 6 C. 9 D. 18
Part 2. Using the information from Part 1, what is the probability that the Burger Bin will sell 12 to 18 burgers an hour? A. 0.136 B. 0.239 C. 0.342 D. 0.475
Please show steps to answers. Thank you.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

a mean of 24 burgers an hour

between 24 and 42 burgers 49.85% of the time

Note: %99.7 of a normal distribution lies within 

3 standard deviations from the mean:  99.7%/2 = 49.85% represents the right side

  z+=+blue%28x+-+mu%29%2Fblue%28sigma%29 = 3

|standard of deviation is 6: as  

  z = (42-24)/highlight%286%29 = 3



With a mean of 24 burgers an hour and sd = 6  

z = (12-24)/6 = -2 and z  = (18-24)/6 = -1

P(12 to 18) = P ( -2 < z < -1) = .158655 - .02275 = .136