SOLUTION: Paul has $3.45 in nickels and dimes. He has 9 more nickels than dimes. How many of each coin does he have? I just need help finding the two equations that I need to solve the p

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Paul has $3.45 in nickels and dimes. He has 9 more nickels than dimes. How many of each coin does he have? I just need help finding the two equations that I need to solve the p      Log On


   

Question 471398: Paul has $3.45 in nickels and dimes. He has 9 more nickels than dimes. How many of each coin does he have?

I just need help finding the two equations that I need to solve the problem.
Answer by faceoff57(108) About Me  (Show Source):
You can put this solution on YOUR website!
.10(x) + .05(x+9) = 3.45
10x + 5x + 45 = 345
15x + 45 = 345
15x = 345 - 45
15x = 300
x = 20
20 dimes and 29 nickels