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Question 471370: Decide whether or not the equation has a circle in its graph. If it does , give the center and the radius. If it does not, describe the graph.
x^2+y^2+10x+4y+25=0
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Decide whether or not the equation has a circle in its graph. If it does , give the center and the radius. If it does not, describe the graph.
x^2+y^2+10x+4y+25=0
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x^2+y^2+10x+4y+25=0
complete the square
(x^2+10x+25)+y^2=-25+25=0
(x+5)^2+y^2=0
Technically, this is a circle with center at (-5,0) with radius=0
With zero radius, circle does not exist.
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