Question 471260: Two nonzero integers, x and y, are such that x+y and y/x are both odd integers.
Let n be the largest integer such that 2^n divides y evenly, and m the largest
such that 2^m divides x evenly. Which is true about n and m?
choose the answer and explain the reason to choose your response
m
m>n
This situation is impossible
m=n
Answer by richard1234(7193)   (Show Source):
You can put this solution on YOUR website! We know that x+y is odd, so this implies that exactly one of x,y is odd. y/x is also an odd integer, so we can say that y = kx, where k is odd. If x is even, then y is also even (e.g. we can have x = 2 and y = 18), and if x is odd, y is odd. However, this contradicts our first statement since the second statement implies that none or both of the integers are odd. Hence, the situation is impossible.
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