SOLUTION: (log16+2log2)/log4=x

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Question 471118: (log16+2log2)/log4=x
Found 3 solutions by nerdybill, Alan3354, bucky:
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
(log16+2log2)/log4=x
(log16+log2^2)/log4=x
(log16+log4)/log4=x
(log16+log4)-log4=x
log16=x
1.204 = x

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
(log16+2log2)/log4=x
(log16+log4)/log4=x
log(64)/log(4) = x
x = 3

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Another way of working this problem:
.
%28log+16+%2B+2log+2%29%2Flog+4+=+x
.
Convert 16 to 2^4 and 4 to 2^2
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%28log+2%5E4+%2B+2log+2%29%2Flog+2%5E2+=+x
.
Bring the exponents out as multipliers of the logarithm terms
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%284log2+%2B2log2%29%2F2log+2+=+x
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Since both terms in the numerator involve log 2, the terms can be added together.
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6+log2%2F2+log+2+=+x
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The log 2 in the numerator cancels with the log 2 in the denominator and you are left with:
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6%2F2+=+x
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Which reduces to x = 3