SOLUTION: Jane is cooking beans and rice for dinner tonight. She has 3 cans of black beans, 1 can of red beans, and 4 cans of garbanzo beans in her cupboard. If she grabs a can of beans with

Algebra ->  Probability-and-statistics -> SOLUTION: Jane is cooking beans and rice for dinner tonight. She has 3 cans of black beans, 1 can of red beans, and 4 cans of garbanzo beans in her cupboard. If she grabs a can of beans with      Log On


   

Question 471011: Jane is cooking beans and rice for dinner tonight. She has 3 cans of black beans, 1 can of red beans, and 4 cans of garbanzo beans in her cupboard. If she grabs a can of beans without looking at the label, what is the probability of her making black beans and rice for dinner?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Basically the question is about the beans (and not the rice)


P(Black Beans) = (# of cans of black beans)/(# of cans total)


P(Black Beans) = 3/8


So the probability is 3/8, which in decimal form is 0.375