SOLUTION: Solve the system by the method of elimination. {-0.04x+0.04y=0.03 {-0.02x+0.04y=0.2 a.(5,23/4) b.inconsistent c.(9,19/2) d.(a,3+4a/4) (dependent) e.(17/2,37/4)

Algebra ->  Systems-of-equations -> SOLUTION: Solve the system by the method of elimination. {-0.04x+0.04y=0.03 {-0.02x+0.04y=0.2 a.(5,23/4) b.inconsistent c.(9,19/2) d.(a,3+4a/4) (dependent) e.(17/2,37/4)      Log On


   

Question 470828: Solve the system by the method of elimination.
{-0.04x+0.04y=0.03
{-0.02x+0.04y=0.2
a.(5,23/4)
b.inconsistent
c.(9,19/2)
d.(a,3+4a/4) (dependent)
e.(17/2,37/4)
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
system%7B-0.04x%2B0.04y=0.03%2C-0.02x%2B0.04y=0.2%29
Subtract the first equation from the second
-0.02x-%28-0.04x%29=0.2-0.03
0.02x=0.17 divide by 0.02
x=0.17%2F0.02
x=17%2F2
Put x=17%2F2 into the first equation
-0.04%2A%2817%2F2%29%2B0.04y=0.03multiply both sides of equation by 100
-4%2A%2817%2F2%29%2B4y=3
-34%2B4y=3
4y=3%2B34
4y=37 divide by 4
y=37%2F4
Answer e.(17/2,37/4)