SOLUTION: If a rock were droped from the top of a building. And the vertical distance the rock dropped doubled every second. What fraction of the building would the rock have traveled in 8 s
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Question 47057: If a rock were droped from the top of a building. And the vertical distance the rock dropped doubled every second. What fraction of the building would the rock have traveled in 8 seconds,if it takes ten seconds for the rock to hit the ground? Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website! F(d) = (9.8)2^(d)/(9.8)2^(10) for 9.8 meters per second as the initial velocity
F(d) = (9.8)(256) = 2508.8/10035.2 = 0.25 = 1/4