Question 470515: Okay, so I've been stuck on this last problem for HOURS now! Can someone please help me figure this out? I think I know the answer to the first one but I'm not sure if its correct... is it .0582? or 58.2% ? Can I use normalCdf or invNorm?
According to a website about salaries, the national average salary as of October 2003 for a human resources clerk was $29,932. We assume that the annual salaries for clerks are normally distributed with a standard deviation of $1,860. (Give your answers correct to two decimal places.)
(a) Find the percentage who earn less than $27,004.
(b) Find the percentage who earn more than $31,892.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! According to a website about salaries, the national average salary as of October 2003 for a human resources clerk was $29,932. We assume that the annual salaries for clerks are normally distributed with a standard deviation of $1,860. (Give your answers correct to two decimal places.)
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(a) Find the percentage who earn less than $27,004.
z(27004) = (27004-29932)/1860 = -1.5742
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P(x < 27004) = P(z < -1.5742) = normalcdf(-100,-1.5742) = 0.0577
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(b) Find the percentage who earn more than $31,892.
normalcdf(31,892,10^99,29932,1860) = 0.1460
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Cheers,
Stan H.
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