Question 470434: Suppose 1.5 percent of the antennas on new Nokia cell phones are defective. For a random
sample of 200 antennas, find the probability that:
a. None of the antennas is defective.
b. Three or more of the antennas are defective.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Suppose 1.5 percent of the antennas on new Nokia cell phones are defective. For a random sample of 200 antennas, find the probability that:
P(defective) = 0.015 ; P(not defective) = 0.985
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a. None of the antennas is defective.
P(none of 200 defective) = 0.985^200 0.0487
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b. Three or more of the antennas are defective.
P(3<= x <=200) = 1 - P(0<= x <=2) = 1 - binomcdf(200,0.015,2) = 0.5785
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Cheers,
Stan H.
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