SOLUTION: physics: an object is released from a plane at an altitude of 1600 ft. the initial velocity is 0ft/s. how many seconds will the object hit the ground? d=vt+16t^2 is the form

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: physics: an object is released from a plane at an altitude of 1600 ft. the initial velocity is 0ft/s. how many seconds will the object hit the ground? d=vt+16t^2 is the form      Log On


   

Question 47013: physics:
an object is released from a plane at an altitude of 1600 ft.
the initial velocity is 0ft/s. how many seconds will the object hit the ground?
d=vt+16t^2 is the formula but I'm just not seeing where this is supposed to all come together. my guess is that it will fall very darn fast.
Found 2 solutions by venugopalramana, Nate:
Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
an object is released from a plane at an altitude of 1600 ft.
the initial velocity is 0ft/s. how many seconds will the object hit the ground?
d=vt+16t^2 is the formula but I'm just not seeing where this is supposed to all come together. my guess is that it will fall very darn fast.
D=1600...V=0
1600=0*T+16*T^2
T^2=1600/16=100
T=10 SEC.

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
The formulas I work with look like this: f%28x%29+=+-16t%5E2+%2B+vt+%2B+h
0+=+-16t%5E2+%2B+1600
0+=+-16%28t%5E2+-+100%29
0+=+-16%28t+-+10%29%28t+%2B+10%29
t = 10 seconds