SOLUTION: help please Use the discriminant to determine the number of real solutions of the equation. 5x^2-3x+1=0

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Question 469726: help please
Use the discriminant to determine the number of real solutions of the equation.
5x^2-3x+1=0

Answer by ccs2011(207) About Me  (Show Source):
You can put this solution on YOUR website!
The discriminant, D is as follows:
given quadratic equation ax%5E2+%2B+bx+%2B+c+=+0
D = b%5E2+-+4ac
If D = 0, then there is only 1 real solution, specifically x = -b/2a
If D > 0, then there are exactly 2 real solutions
If D < 0, then no real solutions exist, graph never crosses x-axis
For this equation 5x%5E2+-+3x+%2B+1+=+0
a = 5
b = -3
c = 1
D = %28-3%29%5E2+-+4%285%29%281%29 = 9+-+20 = -11
-11 < 0
Therefore, no real solutions exist for this equation