SOLUTION: Can soneone please let me know if I am on the right track with this problem, I may have figured the first part out, but I am stumped on the last parts.
The access code for a gar
Algebra ->
Probability-and-statistics
-> SOLUTION: Can soneone please let me know if I am on the right track with this problem, I may have figured the first part out, but I am stumped on the last parts.
The access code for a gar
Log On
Question 469719: Can soneone please let me know if I am on the right track with this problem, I may have figured the first part out, but I am stumped on the last parts.
The access code for a garage door consists of 3 digits. Each digit can be 0 through 7 and each digit can be repeated.
a)find the number of possible codes
b)What is the probability of randomly selecting the correct access code?
c)What is the probability of not selecting the correct access code?
The answer I have for the number of codes is: 290. I am stuck on the rest of the question, I need help. Thanks Found 2 solutions by jorel1380, edjones:Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! The digits are 0 through 7, and can be repeated, so the number of possible codes is 8x8x8=512
----------------
The possibility of randomly finding the right code is 1/512.
The possibility of getting the wrong code is 511/512..
You can put this solution on YOUR website! a) 8^3=512
.
b) 1/512 the probability of selecting the correct access code on the first try.
.
c)511/512 the probability of not selecting the correct access code on the first try.
.
Ed
