SOLUTION: Fred can paint a house in 10 hours. Together, Pat and Fred can paint the house in 8 hours. Which equation, when solved, will produce the number of hours needed for Pat to paint the

Algebra ->  Expressions-with-variables -> SOLUTION: Fred can paint a house in 10 hours. Together, Pat and Fred can paint the house in 8 hours. Which equation, when solved, will produce the number of hours needed for Pat to paint the      Log On


   

Question 469705: Fred can paint a house in 10 hours. Together, Pat and Fred can paint the house in 8 hours. Which equation, when solved, will produce the number of hours needed for Pat to paint the house alone?
Found 2 solutions by jorel1380, ankor@dixie-net.com:
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
1/8-1/10=1/pat
5/40-4/40=1/pat
1/40=1/pat
pat=40 hours..

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Fred can paint a house in 10 hours.
Together, Pat and Fred can paint the house in 8 hours.
Which equation, when solved, will produce the number of hours needed for Pat to paint the house alone?
;
Let t = time required by Pat to do the job alone
Let the completed job = 1 (a painted house)
:
Each man will do a fraction of the job, the sum of the two fractions = 1
;
8%2F10 + 8%2Ft = 1
multiply by 10t, results:
8t + 8(10) = 10t
80 = 10 - 8t
80 = 2t
t = 80%2F2
t = 40 hrs, for Pat to do it alone, (fire this guy)
:
Check this
8/10 + 8/40 =
.8 + .2 = 1