SOLUTION: An artist has 30kg of an alloy that is 45% copper. How many kilograms of a second alloy that is 70% copper should be mixed with the first alloy to get a new alloy that is 60% coppe

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: An artist has 30kg of an alloy that is 45% copper. How many kilograms of a second alloy that is 70% copper should be mixed with the first alloy to get a new alloy that is 60% coppe      Log On


   

Question 469583: An artist has 30kg of an alloy that is 45% copper. How many kilograms of a second alloy that is 70% copper should be mixed with the first alloy to get a new alloy that is 60% copper
Found 2 solutions by jorel1380, stanbon:
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
30x.45=13.5
13.5+.7(n)=.6(30+n)
13.5+.7n=18+.6n
.1n=4.5
n=4.5/.1=45 kilograms of 70% copper needed for the alloy..

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
An artist has 30kg of an alloy that is 45% copper. How many kilograms of a second alloy that is 70% copper should be mixed with the first alloy to get a new alloy that is 60% copper
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Equation:
copper + copper = copper
0.45*30 + 0.70x = 0.60(x + 30)
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Multiply thru by 100 to get:
45*30 + 70x = 60x + 60*30
15*30 = 10x
x = 5 kg (amt of 70% alloy needed)
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Cheers,
Stan H.
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