SOLUTION: (y^3-3y^2)/(y^2+2y-15)=(13y-40)/(y+5)

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Question 469553: (y^3-3y^2)/(y^2+2y-15)=(13y-40)/(y+5)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

%28y%5E3-3y%5E2%29%2F%28y%5E2%2B2y-15%29=%2813y-40%29%2F%28y%2B5%29

y%5E2cross%28%28y-3%29%29%2F%28%28y%2B5%29cross%28%28y-3%29%29%29=%2813y-40%29%2F%28y%2B5%29

  y^2 = 13y - 40

  y^2 - 3y + 40 = 0

  factoring

 (y-8)(y-5) = 0

 (y-8)= 0   y = 8

 (y-5)= 0   y = 5