SOLUTION: (1) Using p=nt-e,find the number of tickets sold (n) if the profit (p) is $350, the price of a ticket (t) is $3, and the expense 9 (e) is $250. (2) Using p=nt-e,find the number

Algebra ->  Expressions-with-variables -> SOLUTION: (1) Using p=nt-e,find the number of tickets sold (n) if the profit (p) is $350, the price of a ticket (t) is $3, and the expense 9 (e) is $250. (2) Using p=nt-e,find the number       Log On


   



Question 469409: (1) Using p=nt-e,find the number of tickets sold (n) if the profit (p) is $350, the price of a ticket (t) is $3, and the expense 9 (e) is $250.
(2) Using p=nt-e,find the number of tickets (n) sold if the profit (p) is $1,350, the price of a ticket (t) is $8, and the expenses (e) is $250.

Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
p=nt-e let solve it for n
p%2Be=nt
nt=p%2Be divide by t
n=%28p%2Be%29%2Ft
(1)if the profit (p) is $350, the price of a ticket (t) is $3, and the expense 9 (e) is $250
n=%28350%2B250%29%2F3=600%2F3=200tickets
(2) if the profit (p) is $1,350, the price of a ticket (t) is $8, and the expenses (e) is $250.
n=%281350%2B250%29%2F8=1600%2F8=200tickets