SOLUTION: I have a couple of questions that I need help with:
1. Solve for x:
ln7 + ln(x-3) = ln(x + 15)
2. Solve for x:
28 = 19 + 12^(x-7)
**The (x-7) is an exp
Question 4694: I have a couple of questions that I need help with:
1. Solve for x:
ln7 + ln(x-3) = ln(x + 15)
2. Solve for x:
28 = 19 + 12^(x-7)
**The (x-7) is an exponent for the number 12
3. Solve for x:
e^(3x-4) = 1/e^(x-12)
**The (3x-4) and (x-12) are both exponents
4. Use the properties of logarithms to write 3lnx^2 + ln(2x-4)-ln(3x-6) as a single logarithm.
To whoever is kind enough to help with answering these problems: Thank you and I would appreciate it if you could show your work so I can better understand how to do these types of problems myself. Thanks again! Found 2 solutions by rapaljer, longjonsilver:Answer by rapaljer(4671) (Show Source):
You can put this solution on YOUR website! 1. ln7 + ln(x-3) = ln(x + 15)
First get the variables on one side (the right side) by subtracting ln(x-3) from each side.
ln 7 = ln(x+15) - ln(x-3)
Use the property of logs to express the right side as a log of a single quantity:
Because ln A = ln B, you can say that A=B. In the same way,
Multiply both sides of the equation by (x-3):
Check to make sure x= 6 doesn't give you the log of a negative. It does not.
2.
Subtract 19 from each side of the equation:
Take the ln of each side:
By law of logarithms:
By distributive property:
Add 7 ln (12) to each side:
Divide both sides by ln (12)
I'm very sorry, that's all I have time for. Maybe someone else will do the others, or perhaps you can repost them.
