SOLUTION: can someone help me solve this problem?
in a certain fraction, the denominator is 5 less than the numerator. if 5 is added to both the numerator and the denominator, the resulti
Algebra ->
Percentage-and-ratio-word-problems
-> SOLUTION: can someone help me solve this problem?
in a certain fraction, the denominator is 5 less than the numerator. if 5 is added to both the numerator and the denominator, the resulti
Log On
Question 469303: can someone help me solve this problem?
in a certain fraction, the denominator is 5 less than the numerator. if 5 is added to both the numerator and the denominator, the resulting fraction is equivalent to 5/4. find the original fraction. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! in a certain fraction, the denominator is 5 less than the numerator. if 5 is added to both the numerator and the denominator, the resulting fraction is equivalent to 5/4. find the original fraction
...
let x=numerator
x-5 = denominator
..
x+5/(x-5+5)=5/4
x+5/x=5/4
5x=4x+20
x=20
original fraction=20/15