SOLUTION: 4) Amanda has 400 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). She wants to maximize the area of her patio (are

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: 4) Amanda has 400 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). She wants to maximize the area of her patio (are      Log On


   

Question 46925: 4) Amanda has 400 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). She wants to maximize the area of her patio (area of a rectangle is length times width). What should the dimensions of the patio be, and show how the maximum area of the patio is calculated from the algebraic equation. Use the vertex form to find the maximum area.

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
2L+2W=400 THUS THE MAXIMUN AREA OF A RECTANGLE IS A SQUARE THUS W=L OR
L~2=400 OR OR L=20 AND W=20 THUS THE BEST RETANGLE IS 20 BY 20 FOR A 400 FOOT
FENCE.