SOLUTION: There were 44, 000 people at a ball game in LA. The day’s receipts were $369,000. How many people paid $13.00 for reserved seats and how many paid $6.00 for general admission? I

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: There were 44, 000 people at a ball game in LA. The day’s receipts were $369,000. How many people paid $13.00 for reserved seats and how many paid $6.00 for general admission? I      Log On

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Question 469046: There were 44, 000 people at a ball game in LA. The day’s receipts were $369,000. How many people paid $13.00 for reserved seats and how many paid $6.00 for general admission?
I think I've part of it, but i can't figure out where to start solving it?
this is what i have so far...
X = the number of people that paid $ 13
Y = the number of people that paid $ 6
X + Y = 44,000 (total number of people that attended)
13x+6Y=369,000 ( total revenue)

Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
m+n=44000
6m+13n=369000
6m+6n=264000
7n=105000
n=15000
m=29000
29000 paid for general admission and 15000 paid for reserved seats..