SOLUTION: I am so stuck on this problem. Please help. This is a deck of 20 cards. You have 4 rows of cards and they are numbered from 1-5 as follow. First row - 1, 2, 3, 4, 5 Second ro

Algebra ->  Probability-and-statistics -> SOLUTION: I am so stuck on this problem. Please help. This is a deck of 20 cards. You have 4 rows of cards and they are numbered from 1-5 as follow. First row - 1, 2, 3, 4, 5 Second ro      Log On


   



Question 469028: I am so stuck on this problem. Please help. This is a deck of 20 cards.
You have 4 rows of cards and they are numbered from 1-5 as follow.
First row - 1, 2, 3, 4, 5
Second row - 1, 2, 3, 4, 5
third row - 1, 2, 3, 4, 5
forth row - 1, 2, 3, 4, 5
Two cards are selected at random from this deck. Determine the probability of both cards being even numbers.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
I am so stuck on this problem. Please help. This is a deck of 20 cards.
You have 4 rows of cards and they are numbered from 1-5 as follow.
First row - 1, 2, 3, 4, 5
Second row - 1, 2, 3, 4, 5
third row - 1, 2, 3, 4, 5
forth row - 1, 2, 3, 4, 5
Two cards are selected at random from this deck. Determine the probability of both cards being even numbers.
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# of even cards is 8
total # of cards is 20
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P(select 2 even) = 8C2/20C2 = 28/190 = 0.1474
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Cheers,
Stan H.
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