SOLUTION: candy selling for $2 per pound is to be mixed with candy selling for $6 per pound. how many pounds of the more expensive candy are needed to produce a 24-pound mixture taht sells

Algebra ->  Conversion and Units of Measurement -> SOLUTION: candy selling for $2 per pound is to be mixed with candy selling for $6 per pound. how many pounds of the more expensive candy are needed to produce a 24-pound mixture taht sells       Log On


   



Question 468960: candy selling for $2 per pound is to be mixed with candy selling for $6 per pound. how many pounds of the more expensive candy are needed to produce a 24-pound mixture taht sells for $5 per pound?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Value ---------------- quantity
Candy I 6 ---------------- x pounds
Candy II 2 ---------------- 24 - x pounds
Mixture 5.00% ---------------- 24

6x+2(24-x)=5*24
6x+48-2x =120
6x-2x=120-48
4x=72
/4
x=18 pounds 6.00% Candy I
6 pounds 2.00% Candy II