Question 468759: This question is about Factoring the sum and difference of two cubes.
8a(cube)- 64 =
Answer by algebrahouse.com(1659)   (Show Source):
You can put this solution on YOUR website! 8a³ - 64
It is a difference of two cubes in the form a³ - b³,
it factors into the form (a - b)(a² + ab + b²)
If a³ is 8a³, then a is 2a {the cube root of 8a³}
If b³ is 64, then b is 4 {the cube root of 64}
8a³ - 64
= (2a - 4)(4a² + 8a + 16) {substituted 2a, in for a, and 4, in for b, into (a - b)(a² + ab + b²)}
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