SOLUTION: solve for x log2(x+2) + log2x=3
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Question 46867
This question is from textbook
COLLEGE ALGEBRA
:
solve for x
log2(x+2) + log2x=3
This question is from textbook
COLLEGE ALGEBRA
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consc198(59)
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log2(x+2) + log2x=3
0.301029995 (x+2) + 0.301029995 . x = 3
0.301029995x + 0.60205999 + 0.301029995x = 3
0.301029995x + 0.301029995x = 3 + 0.60205999
0.6020599 = 3.60205999
3.60205999 - 0.6020599 = 3.00000009
Answer = 3.00000009