SOLUTION: i have tried to solve this log2(8-6x)=5. i cant seem to figure out what i am doing wrong. i have tried this: 2^5=8-6x. and so i add 8 to both sides and i get 40=6x then i divide

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: i have tried to solve this log2(8-6x)=5. i cant seem to figure out what i am doing wrong. i have tried this: 2^5=8-6x. and so i add 8 to both sides and i get 40=6x then i divide       Log On


   

Question 468526: i have tried to solve this log2(8-6x)=5. i cant seem to figure out what i am doing wrong. i have tried this: 2^5=8-6x. and so i add 8 to both sides and i get 40=6x then i divide both sides by 6 and i 6.666666? please help... thankyou
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
log%282%2C%288-6x%29%29=5
8-6x=2%5E5
Subtract 8 from both sides of the equation
-6x=32-8
-6x=24
Divide both sides by -6
x=-24%2F6
x=-4