SOLUTION: Find three consecutive odd integers such that three times the first integer is one less than the sum of the second and third integers

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Question 468394: Find three consecutive odd integers such that three times the first integer is one less than the sum of the second and third integers
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
3(n)+1=(n+2)+(n+4)
3n+1=2n+6
n=5
n+2=7
n+4=9
The numbers are 5, 7, and 9..