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Hi,
f(x) = x3 + 5x2 + 6x + 2 | x = -1 a root as -1 + 5 - 6 + 2 = 0
Using synthetic division
(x3 + 5x2 + 6x + 2)/(x+1) = x^2 + 4x + 2
-1 1 5 6 2
-1 -4 -2
1 4 2 0
(x+1)(x^2 + 4x + 2)
zeros are: -1, -2+sqrt(2),-2-sqrt(2)