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Hi,
(2x3 - 23x2 + 71x - 30)/(x-5) = 2x^2 -13x + 6
Using synthetic division to determine the 2x^2 -13x + 6
5 2 -23 71 -30
10 -65 30
2 -13 6 0
(x-5)(2x^2 - 13x + 6) = 0
factoring
(x-5)(2x -1)(x-6) = 0
(x-5)= 0 x= 5
(2x -1)= 0 x= 1/2
(x-6) = 0 x= 6