SOLUTION: Does the equation 3(x-1)+5=15x+7-4-4(3x+1)+3 has infinitely many solutions, one solution, or no solution?
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Question 467820
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Does the equation 3(x-1)+5=15x+7-4-4(3x+1)+3 has infinitely many solutions, one solution, or no solution?
Answer by
rfer(16322)
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3x-3+5=15x-4-12x-4+3
3x+2=3x+3
3x-3x=1
no solution