SOLUTION: The amount of a radioactive tracer remaining after t days is given by A=A0 e^-0.058t, where A0 is the starting amount at the beginning of the time period. How many days will it tak

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: The amount of a radioactive tracer remaining after t days is given by A=A0 e^-0.058t, where A0 is the starting amount at the beginning of the time period. How many days will it tak      Log On


   



Question 46771This question is from textbook
: The amount of a radioactive tracer remaining after t days is given by A=A0 e^-0.058t, where A0 is the starting amount at the beginning of the time period. How many days will it take for one half of the original amount to decay?
10 days
11 days
12 days
13 days
Thanks
This question is from textbook

Answer by adamchapman(301) About Me  (Show Source):
You can put this solution on YOUR website!
A=A%5B0%5D+e%5E-0.058t
A=A%5B0%5D%2F2
So:
A%5B0%5D%2F2=A%5B0%5D+e%5E-0.058t
Dividing by A%5B0%5D:
1%2F2=e%5E-0.058t
ln%280.5%29=-0.058t
t=-ln%280.5%29%2F0.058
t=11.9508 days.

I hope this helps,
Adam
P.S. please visit my website, it may be helpful to you. The address is www.geocities.com/quibowibbler