Question 467539: two cyclists, 90 miles apart, start riding toward each other at the same time. one cycles twice as fast as the other. If they meet 2 hour later, at what average speed is each cyclist traveling?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! two cyclists, 90 miles apart, start riding toward each other at the same time. one cycles twice as fast as the other. If they meet 2 hour later, at what average speed is each cyclist traveling?
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Their average speed is 45 mph
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Equation:
x + 2x = 45 mph
3x = 45
x = 15 (one of the cyclists averages 15 mph)
2x = 30 mph (the other cyclists averages 30 mph)
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Cheers,
Stan H.
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