SOLUTION: find two consecutive odd integers if the sum of their squares is 290

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Question 467521: find two consecutive odd integers if the sum of their squares is 290
Answer by amoresroy(361) About Me  (Show Source):
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find two consecutive odd integers if the sum of their squares is 290
Let x = the smaller odd integer
x+2 = the larger odd integer
x^2 + (x+2)^2 = 290
x^2 + x^2 + 4x + 4 = 290
2x^2 + 4x - 286 = 0
x^2 + 2x - 143 = 0
Solve by factoring
(x+13)(x-11) = 0
x-11 = 0
x = 11
x+2 = 11+2 = 13
The two consecutive odd integers are 11 and 13.