Question 467134: There are 75 more women than men enrolled in Linden College. If there are "n" men enrolled, then, in terms of "n", what percent of those enrolled are men?
The answer is [(100n)/ (2n+75)]%
I do not understand how they got this answer.
Can you help?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! There are 75 more women than men enrolled in Linden College. If there are "n" men enrolled, then, in terms of "n", what percent of those enrolled are men?
The answer is [(100n)/ (2n+75)]%
I do not understand how they got this answer.
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# of men = "n"
# of women = "n+75"
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Total # of students: n + n+75 = 2n+75
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% of men = n/(2n+75)
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Converting that to percentage notation you get:
100[n/(2n+75)]/100
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= [100n/[(2n+75)/100]
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= [100n/(2n+75)%]
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Cheers,
Stan H.
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