SOLUTION: if the average of 5 consecutive even numbers is 46, then the largest number is

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Question 467073: if the average of 5 consecutive even numbers is 46, then the largest number is
Found 3 solutions by Big Poop, josmiceli, Alan3354:
Answer by Big Poop(157) About Me  (Show Source):
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
If the smallest number is n, then
The five consecutive even numbers are
n, n%2B2, n+%2B4, +n%2B6, and n%2B8
given:
+%28+n+%2B+n+%2B+2+%2B+n+%2B+4+%2B+n+%2B+6+%2B+n+%2B+8%29+%2F+5+=+46+
+%285n+%2B+20%29+%2F+5+=+46+
+5n+%2B+20+=+230+
+5n+=+210+
+n+=+42+
+n+%2B+2+=+44+
+n+%2B+4+=+46+
+n+%2B+6+=+48+
+n+%2B+8+=+50+
The largest number is 50
check:
+%285n+%2B+20%29+%2F+5+=+46+
+%285%2A42+%2B+20%29+%2F+5+=+46+
+%28210+%2B+20%29+%2F+5+=+46+
+230%2F5+=+46+
+230+=+230+
OK

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
if the average of 5 consecutive even numbers is 46, then the largest number is
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If the avg = 46, then 46 is the middle number
--> 42, 44, 46, 48 & 50