I get log base 2^3^(x-2)= 3x+1 and I am stuck after this. Any suggestions?
Thanks so much Found 2 solutions by Alan3354, ccs2011:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! 2^(3x+1)= 3^(x-2)
(3x+1)*log(2) = (x-2)*log(3)
3x*log(2) + log(2) = x*log(3) - 2log(3)
x*log(8) - x*log(3) = -log(2) - log(9)
x*log(8/3) = -log(18)
x = -log(18)/log(8/3)
x =~ -2.9469
You can put this solution on YOUR website! Good so far, took log of both sides
For simplicity sake, when I use log i am using log base 2.
From here you need to use the following log property:
This will get the variable x out of the exponent
Distribute right side
Get x's on left side, constants on right
Factor out the x on left, and factor out negative on right
Divide by (3 - log 3) on both sides
If you use your calculator this is approximately
