SOLUTION: 5^x=4^(x+1) I can't figure out how to solve this the answer is 6.2126 but I get as far as log base 5 4^(x+1)=x I have tried dividing log(4^(x+1)) into log(S) and get no where

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: 5^x=4^(x+1) I can't figure out how to solve this the answer is 6.2126 but I get as far as log base 5 4^(x+1)=x I have tried dividing log(4^(x+1)) into log(S) and get no where      Log On


   



Question 466760: 5^x=4^(x+1)
I can't figure out how to solve this the answer is 6.2126 but I get as far as
log base 5 4^(x+1)=x I have tried dividing log(4^(x+1)) into log(S) and get no where near the answer. Any help please? Thanks so much

Answer by ccs2011(207) About Me  (Show Source):
You can put this solution on YOUR website!
Use the following log property:
log+x%5En+=+n%2Alog+x
When i use log I'm implying log base 5.
x+=+log+4%5E%28x%2B1%29
x+=+%28x%2B1%29log+4
Distribute
x+=+xlog+4+%2B+log+4
Get x's on left side
x+-+xlog+4+=+log+4
Factor out an x
x%281+-+log+4%29+=+log+4
Divide
x+=+log+4%2F%281+-+log+4%29