SOLUTION: An urn has 8 red and 4 white balls. We draw 2 balls from the urn without replacement. If we assume that at each draw each ball in the urn is equally likely to be chosen, what is th

Algebra ->  Probability-and-statistics -> SOLUTION: An urn has 8 red and 4 white balls. We draw 2 balls from the urn without replacement. If we assume that at each draw each ball in the urn is equally likely to be chosen, what is th      Log On


   



Question 466597: An urn has 8 red and 4 white balls. We draw 2 balls from the urn without replacement. If we assume that at each draw each ball in the urn is equally likely to be chosen, what is the prob. that both balls drawn are red?
maybe 8/12 * 7/11 ???

Answer by sudhanshu_kmr(1152) About Me  (Show Source):
You can put this solution on YOUR website!

yes you are right, probability = 8/12 *7/11