SOLUTION: During the first part of a trip a canoeist travels 46 miles at a certain speed. The canoeist travels 16 miles on the second part of the trip at a speed 5 mph slower. The total ti
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Question 466444: During the first part of a trip a canoeist travels 46 miles at a certain speed. The canoeist travels 16 miles on the second part of the trip at a speed 5 mph slower. The total time for the trip was 5 hours. What was the speed for each part of the trip? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! During the first part of a trip a canoeist travels 46 miles at a certain speed. The canoeist travels 16 miles on the second part of the trip at a speed 5 mph slower. The total time for the trip was 5 hours. What was the speed for each part of the trip?
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let x=speed of first part of trip
x-5 = speed of second part of trip
Travel time = distance/speed
46/x+16/(x-5)=5
LCD:x(x-5)
46(x-5)+16x=5(x)(x-5)
46x-230+16x=5x^2-25x
5x^2-87x+230=0
Solve by quadratic formula below:
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..
a=5, b=-87, c=230
x=[-(-87)ħsqrt((-87)^2-4*5*230)]/2*5
x=[87ħsqrt(2969)]/10
x=[87ħ54.49]/10
x=14.15
or
x=3.25 (reject,x-5>0)
Ans:
Speed of first trip=14.15 mph
Speed of second trip=14.15-5=9.15 mph
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