SOLUTION: i seriously need some help with this problem! in 1993, the life expectancy of males in a certain country was 66.8 years. in 2000, it was 70.4 years. let E represent the life exp

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Question 466432: i seriously need some help with this problem! in 1993, the life expectancy of males in a certain country was 66.8 years. in 2000, it was 70.4 years. let E represent the life expectancy in year t and let t represent the number of years since 1993.
the linear function that fits the data is E(t) = ?t + ?
use the function to predict the life expectancy of males in 2003.
E(10) = ?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
In 1993, the life expectancy of males in a certain country was 66.8 years.
in 2000, it was 70.4 years.
let E represent the life expectancy in year t and let t represent the number of years since 1993.
:
Find the slope
In 1993; x1=0 and y1=66.8
In 2000; x2=7 and y2=70.4
:
Find the slope (m) using the slope equation: m = %28y2-y1%29%2F%28x2-x1%29
m = %2870.4-66.8%29%2F%287+-+0%29%29 = %283.6%29%2F%287%29 =
:
Use the point/slope formula to write the equation; y - y1 = m(x - x1)
y - 66.8 = 3.6%2F7(x - 0)
y = 3.6%2F7x + 66.8
:
therefore:
The Linear function E(t) that fits the data is.
E(t)= 3.6%2F7t + 66.8
:
Use the Function to predict the life expectancy of males in 2003.
This means t=10; substitute 10 for t in the equation
E(10)= 3.6%2F7(10) + 66.8
E(10)= 5.1 + 66.8
E(10)~ 72 yrs is the life expectancy in 2003