SOLUTION: Use slopes to show that the square with vertices at (-2, 5), (4, 5), (4, -1), and (-2, -1) has diagonals that are perpendicular.

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Question 466430: Use slopes to show that the square with vertices at (-2, 5), (4, 5), (4, -1), and
(-2, -1) has diagonals that are perpendicular.
Found 2 solutions by Gogonati, lwsshak3:
Answer by Gogonati(855) About Me  (Show Source):
You can put this solution on YOUR website!
The slope of the diagonal AC is: m%5B1%5D=%28-1-5%29%2F%284%2B2%29=-1, and the slope of the
diagonal BD is:m%5B2%5D=%28-1-5%29%2F%28-2-4%29=%2B1, since the product of their slopes is
-1 the diagonals are perpendicular. (m%5B1%5D%2Am%5B2%5D=-1%2A1=-1).

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Use slopes to show that the square with vertices at (-2, 5), (4, 5), (4, -1), and
(-2, -1) has diagonals that are perpendicular.
...
slope of diagonal connecting (-2,5) and (4,-1):
m1=∆y/∆x=5-(-1)/-2-4=6/-6=-1
..
slope of diagonal connecting (4,5) and (-2,-1):
m2=∆y/∆x=5-(-1)/4-(-2=6/6=1
Since m1 and m2 are negative reciprocals, they are perpendicular to each other