Question 466399: I cannot seem to get the answer to this question.
4+2/x/3+1/6
A)1 b 12/x c 12 d x/12
any help would be appreciated.. thanks
Found 2 solutions by Scorinitron, richard1234:
Answer by Scorinitron(19)   (Show Source):
You can put this solution on YOUR website! 1.)
4+(2)/(x)/(3)+(1)/(6)
To divide by 3, multiply by the reciprocal.
4+(2)/(x)*(1)/(3)+(1)/(6)
Multiply 2 by 1 to get 2.
4+(2)/(3*x)+(1)/(6)
Multiply x by 3 to get 3x.
4+(2)/(3x)+(1)/(6)
To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is 6x. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions.
4*(6x)/(6x)+(2)/(3x)*(2)/(2)+(1)/(6)*(x)/(x)
Multiply 4 by 6x to get 24x.
(24x)/(6x)+(2)/(3x)*(2)/(2)+(1)/(6)*(x)/(x)
Multiply 2 by 2 to get 4.
(24x)/(6x)+(4)/(2*3x)+(1)/(6)*(x)/(x)
Multiply 3x by 2 to get 6x.
(24x)/(6x)+(4)/(6x)+(1)/(6)*(x)/(x)
Multiply 1 by x to get x.
(24x)/(6x)+(4)/(6x)+(x)/(x*6)
Multiply 6 by x to get 6x.
(24x)/(6x)+(4)/(6x)+(x)/(6x)
Combine the numerators of all expressions that have common denominators.
(24x+4+x)/(6x)
According to the distributive property, for any numbers a, b, and c, a(b+c)=ab+ac and (b+c)a=ba+ca. Here, x is a factor of both 24x and x.
((24+1)x+4)/(6x)
Add 1 to 24 to get 25.
((25)x+4)/(6x)
Remove the parentheses.
Answer: (25x+4)/(6x)
2).
*Note:*I'm Assuming the "A)" has nothing to do with the equation so here are the steps.*
(1b^(12))/(xc^(12)dx)/(12)
Add 1 to 1 to get 2.
((1b^(12))/(x^(2)))/(12)
Combine all similar variables in the expression.
((1b^(12))/(dx^(2)c^(12)))/(12)
Arrange the variables alphabetically within the expression (1b^(12))/(dx^(2)c^(12)). This is the standard way of writing an expression.
((b^(12))/(c^(12)dx^(2)))/(12)
Multiply the factor by the rest of the expression to remove the fraction from the denominator. To multiply by a factor in the denominator, multiply by 1 over the factor.
(1)/(12)*(b^(12))/(c^(12)dx^(2))
Multiply 1 by b^(12) to get b^(12).
(b^(12))/(c^(12)dx^(2)*12)
Multiply 12 by c^(12)dx^(2) to get 12c^(12)dx^(2).
Answer: (b^(12))/(12c^(12)dx^(2))
Answer by richard1234(7193)  (Show Source):
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