SOLUTION: Solve the problem by setting up and solving an appropriate algebraic equation.
How many milliliters of pure acid must be added to 150 milliliters of a 40% solution of acid to obta
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How many milliliters of pure acid must be added to 150 milliliters of a 40% solution of acid to obta
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Question 466370: Solve the problem by setting up and solving an appropriate algebraic equation.
How many milliliters of pure acid must be added to 150 milliliters of a 40% solution of acid to obtain a 50% solution?
_________ml Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How many milliliters of pure acid must be added to 150 milliliters of a 40% solution of acid to obtain a 50% solution?
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acid + acid = acid
1.00x + 0.40*150 = 0.50*(x+150)
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Multiply thru by 100 to get:
100x + 40*150 = 40x + 50*150
60x = 10*150
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x = (1/6)150
x = 50 ml (amt. of pure acid needed)
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Cheers,
Stan H.
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