SOLUTION: Write an equation for the line perpendicular to y = 2x - 5 that contains (-9,6). a) y-6=2(x+9) b) x-6=2(y+9) c) y-9=1/2(+6) d) y-6=1/2(x+9)

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Question 466357: Write an equation for the line perpendicular to y = 2x - 5 that contains (-9,6).
a) y-6=2(x+9)
b) x-6=2(y+9)
c) y-9=1/2(+6)
d) y-6=1/2(x+9)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Write an equation for the line
perpendicular to y = 2x - 5 that contains (-9,6).
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The given line has slope = 2
Any line perpendicular to it must have slope = (-1/2)
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Form:
y = mx + b
Solve for "b":
6 = (-1/2)(-9) + b
6 = (9/2) + b
b = 3/2
----------------
Equation:
y = (-1/2)x + (3/2)
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Cheers,
Stan H.
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a) y-6=2(x+9)
b) x-6=2(y+9)
c) y-9=1/2(x+6)
d) y-6=1/2(x+9)