Question 466183: let n(x)= -12x^4 + 3x^3 - x^2 + 15 find n(-5)
is 2 a zero of q(x) = x^4 - 5x^2 + 6? , square root3?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! let n(x)= -12x^4 + 3x^3 - x^2 + 15 ; find n(-5)
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n(-5) = -12(-5)^4 + 3(-5)^3 - (-5)^2 + 15
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n(-5) = -12(625) - 375 - 25 + 15
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n(-5) = -7885
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is 2 a zero of q(x) = x^4 - 5x^2 + 6? ,
q(2) = 2^4 - 5(2)^2+6
q(2) = 16 - 20 + 6
q(2) = 2
Since f(2) is not zero, 2 is not a zero of q(x).
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Is square root3 a zero of q(x)?
q(sqrt(3)) = (sqrt(3))^4 - 5(sqrt(3))^2 + 6
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q(sqrt(3)) = 9 -15 + 6 is zero
So sqrt(3) is a zero of q(x)
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Cheers,
Stan H.
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