SOLUTION: In quarters dimes and nickels equaling 24.15. find the number of each kind if there are twice as many nickels as quarters and five more dimes than nickels.

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Question 466174: In quarters dimes and nickels equaling 24.15. find the number of each kind if there are twice as many nickels as quarters and five more dimes than nickels.
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
In quarters dimes and nickels equaling 24.15. find the number of each kind if there are twice as many nickels as quarters and five more dimes than nickels.
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Equations:
5n + 10d + 25q = 2415 cents
n = 2q
d = n+5
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Substitute for "q" and for "d"; solve for "n":
5n + 10(n+5) + 25(n/2) = 2415
10n + 20n+100 + 25n = 4830
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55n = 4730
n = 86 (# of nickels)
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q = n/3 = 43 (# of quarters)
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d = n+5 = 91 (# of dimes)
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Cheers,
Stan H.
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Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!
Let = number of quarters
Let = number of dimes
Let = number of nickels
given:
(1) (in cents)
(2)
(3)
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From (2)
(2)
Substitute (2) and (3) in (1)
(1)
(1)
Multiply both sides by
(1)
(1)
(1)
and, since
(3)
(3)
(3)
and
(2)
(2)
(2)
43 = number of quarters
91 = number of dimes
86 = number of nickels
check answer:
(1)
(1)
(1)
OK